Posted by: Maybelline@
Holy smokes, what a crazy and exciting week it has been! The Firebird Festival has come to end, but please don’t be sad. Our awesome feathered friends will be back again next year to celebrate with us once more. This week we will pay a visit to my friend @Finneous+ and see what he has going on at the Boutique con Carne. Do you think you have what it takes to get through this Enigma with a glorious reward or will you fall into my trap? Good luck, everyone!
I am astonished by how many people I stumped with this one! I guess this was a lot harder than I intended. I am sorry! As with the last Enigma, there were a couple of ways to solve it but for those that I did manage to confuse, here’s how to easiest way to solve this puzzle.
First off, think of the sparkler as a flat 2D object rather than a 3D one. Cutting and unrolling the cardboard tube from a roll of paper towels will give a 2D representation of what this would look like.
Convert the inches to centimeters for the total length of the sparkler. 15.748 inches = 40 centimeters
6/8 of length of the total length of the sparkler is 30 centimeters. This is the portion of the wooden base that is covered by the explosive cord.
The space between each coil can be figured out by 30 cm total space / 10 coils within the space; 3 cm.
Using the Pythagorean Theorem; we will be able to solve for how long 1 coil is or C in the above diagram. From above we know: A = 4 cm [diameter of the sparkler] and B = 3 cm
10 coils per sparkler = 50 cm of explosive coil needed per sparkler
1250 centimeters of explosive cord is needed to make the entire box of Seregan Sparklers.
15 people participated and 0 got it correct
I have an honorable mention to @Charles as their guess of 3141.593; was the closest.